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Math 221 Week 4 part 2 Trigonometric functions: limits and derivatives Please take a moment to just breathe. We define sinθ, cosθ, and tanθ using the unit circle. Note that by similar triangles, tanθ = sinθ In this section: 1 cosθ We review the trigonometric functions. We prove that lim sinh = 1. h→0 h We derive the derivative of several trigonometric functions. 1 sinθ tanθ θ cosθ We will show that To compute the derivatives, we will need the following limits. d lim sinh = 1 lim cos h − 1 = 0 dt sin t = cos t . h→0 h h→0 h As evidence of the first limit, recall that the arc of a unit circle of angle θ has length θ. The line segment representing sinθ appears to have nearly the position of the mass: same length as the bit of arc. p(t) = sin t velocity of the mass: p′( t) = cos t Proof using Squeeze Theorem that lim sinh = 1. + h h→0 For h in the interval [0, π/2], The proofs that sinh ≤ h ≤ tanh, so lim sinh = 1 and lim cosh − 1 = 0 h 1 h→0− h h→0 h 1 ≤ sinh ≤ cosh are similar. By the Squeeze Theorem, since lim 1 =1, We will also need these formulas: h h→0+ cosh lim =1. sin(x + h) = sin xcosh + cosxsinh + sinh h→0 cos(x + h) = sin xsinh − cosxcosh We have Use the limit definition to compute the derivative of sin x: d sinx = cosx d sin(x + h) − sin x dx dx sinx = lim h and a similar computation shows h→0 =lim sinxcosh+cosxsinh−sinx d cosx = −sinx h→0 h dx =lim sinxcosh−sinx+cosxsinh Exercise: compute d tan x using the quotient rule. h→0 h dx =lim[sinxcosh−1 +cosxsinh] = cosx (Please pause the video and try it yourself!) h→0 h h Trigonometric functions and their derivatives. d tanx = d [sinx] dx dx cosx sin x cos x tan x sec2 x = (sinx)′( cosx) − (sin x)(cosx)′ secx sec x tan x cos2x cosx −sin x cot x −csc2 x = (cosx)(cosx)−(sinx)(−sinx) cscx −csc x cot x cos2x If a trigonometric function starts with “co”, then its derivative 2 2 has a negative sign. = (cosx) +(sinx) = 1 =sec2x Please memorize these. cos2x cos2x A side note about lim sinh = 1 h→0 h In practice, the approximation sinh ≈ h for small h is very useful. If we want to speed up the oscillation, we also have lim sin(2h) = 1, etc. h→0 2h Here is the full “Taylor series” for sin x from Calc II. sinh = h−h3/3!+h5/5!−h7/7!−h9/9!+.... The more terms you take, the better the approximation will be.
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